-x^2-2x+3=4/5x-2

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Solution for -x^2-2x+3=4/5x-2 equation: 


x in (-oo:+oo)

(-x)^2-(2*x)+3 = (4/5)*x-2 // - (4/5)*x-2

(-x)^2-(2*x)-((4/5)*x)+2+3 = 0

(-x)^2-2*x+(-4/5)*x+2+3 = 0

x^2-14/5*x+5 = 0

DELTA = (-14/5)^2-(1*4*5)

DELTA = -304/25

DELTA < 0

x belongs to the empty set

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